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Control Systems
Which of the following combinations is/are correct electrical analogous elements in force-current analogy?
All of these
Spring element (K) --------- Inverse inductance (1/L)
Velocity (v) ----------------- Voltage (V)
Force (f) --------------------- Current (i)
All of these
Spring element (K) --------- Inverse inductance (1/L)
Velocity (v) ----------------- Voltage (V)
Force (f) --------------------- Current (i)
Answer
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Related Question
Control Systems
The transfer function of phase lead compensator is given by , where, T > 0, α < 0. What is the maximum phase shift provided by this compensator?
sin-1((1 - α)/(1 + α)
cos-1((1 - α)/(1 + α)
tan-1((1 - α)/(2√α)
both 1 and 3
sin-1((1 - α)/(1 + α)
cos-1((1 - α)/(1 + α)
tan-1((1 - α)/(2√α)
both 1 and 3
Answer
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Control Systems
The impulse response of a system is c(t) = -te-t + 2 e-t (t>0). Its open loop transfer function is
(2s+2)/(s+1)²
(2s+2)/s²
(2s+1)/(s+1)²
(2s+1)/s²
(2s+2)/(s+1)²
(2s+2)/s²
(2s+1)/(s+1)²
(2s+1)/s²
Answer
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Control Systems
Lead network is used to
both A and C.
improve steady state response.
improve transient response.
increase bandwidth.
both A and C.
improve steady state response.
improve transient response.
increase bandwidth.
Answer
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Control Systems
In the integral control of the single area system frequency error is reduced to zero. Then
integrator o/p increases but speed changer position comes down.
integrator output and speed changer position attain a constant value.
integrator o/p decreases and speed changer position comes down.
integrator o/p decreases but speed changer position moves up.
integrator o/p increases but speed changer position comes down.
integrator output and speed changer position attain a constant value.
integrator o/p decreases and speed changer position comes down.
integrator o/p decreases but speed changer position moves up.
Answer
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Control Systems
At which frequency does the Bode magnitude plots for the functions K/S2 have gain crossover frequency
ω = K rad/sec.
ω = 0 rad/sec.
ω = √K rad/sec.
ω = K2 rad/sec.
ω = K rad/sec.
ω = 0 rad/sec.
ω = √K rad/sec.
ω = K2 rad/sec.
Answer
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