Related Question
Condition of good conductor:
σ/ϵω >> 1
Equation is given by:
The constant ratio = σ/ϵω
= 44913.6
σ/ϵω >> 1.
hence sea water is a acting as a good conductor Since attenuation is 90%, so transmission is 10%
So,
e^(-αx) = 0.1
Attenuation constant = √(σμϵ/2)
= 0.702
-αx = ln(0.1)
x = 3.27 m
For the given question,
Ib = 0
Ia = -Ic
Calculation:
Ia1 = 1/3*(Ia + a*Ib + a²*Ic)
= 1/3*(15 + 15∟-120°)
= 7.5 + j*4.33 A
Ia2 = 1/3*(Ia + a²*Ib + a*Ic)
= (1/3)*(15 + 15∟120°)
= 7.5 - j*4.33 A
Iao = (1/3)*(Ia + Ib + Ic)
= (Ia - Ia)
= 0