EE MCQ

MGVCL Exam Paper (30-07-2021 Shift 1)
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Three resistances 750 Ω, 600 Ω and 200 Ω are connected in parallel. The total current is 1 A. Determine the voltage applied.

Equivalent resistance of the circuit, Req = (750|| 600 || 200)

Req = 125 Ω

Current from source = 1 A

Source voltage = 1*125

Source voltage = 125 V

Related Question

MGVCL Exam Paper (30-07-2021 Shift 1)
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The expression for voltage regulation of a short transmission line for lagging power factor is given by: ___, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resistance and 'X' is the line reactance.

For lagging power factor = (IR*cosφ + Ixsinφ)/Vr

For leading power factor = (IR*cosφ - Ixsinφ)/Vr

Zero voltage regulation occurs on leading power factor only.

MGVCL Exam Paper (30-07-2021 Shift 1)
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Rearrange the following to form a meaningful sentence and find the most logical order from the given options.

P: 60 countries using dance as a tool for

Q: building social cohesion and resolving

R: conflict throughout the world

S: battery Dance has travelled far and wide across

P: 60 countries using dance as a tool for

Q: building social cohesion and resolving

R: conflict throughout the world

S: battery Dance has travelled far and wide across

MGVCL Exam Paper (30-07-2021 Shift 1)
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The single line diagram of the simple system is shown in figure the corresponding reactance diagram is

Simple logic of reactance diagram is that simplified equivalent circuit of power system in which the various components of power system are represented by their reactance.

The reactance diagram can be obtained from impedance diagram if all the resistive components are neglected.

So, from figure each of the component is represented by its reactance.

MGVCL Exam Paper (30-07-2021 Shift 1)
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Case 1: The PV connected to the DC bus was injecting 20 kW of power constituting of 1 kW of loss

Case 2: The same PV is connected to the AC bus constituting to 1.5 kW loss. Find out the change in efficiency from Case 1 to Case 2?

Case 2: The same PV is connected to the AC bus constituting to 1.5 kW loss. Find out the change in efficiency from Case 1 to Case 2?

In DC microgrid system,

Efficiency α 1/Pin

For 1 kW loss injecting power is 20 kW

For 1.5 kW loss injecting power will be proportional to 30 kW

So,

Efficiency will be reduced 0.025