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Control Systems
The transfer function of a plant is T(s) = 5/(s+5)(s² + 5 + 1). The second order approximation of T(s) using dominant pole concept is
5/(s² + 5 + 1)
1/(s+1)(s+5)
1/(s² + 5 + 1)
5/(s+1)(s+5)
5/(s² + 5 + 1)
1/(s+1)(s+5)
1/(s² + 5 + 1)
5/(s+1)(s+5)
Answer
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Related Question
Control Systems
The transfer function of a system is 10/(1 + S) when operated as a unity feedback system, the steady state error to a unit step input will be
Zero.
1/11.
10.
¾.
Zero.
1/11.
10.
¾.
Answer
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Control Systems
When writing a transfer function which of the following loops are not valid loops?
Self loops at input node.
Neither 1 nor 2.
Self loops at output node.
Both 1 and 2.
Self loops at input node.
Neither 1 nor 2.
Self loops at output node.
Both 1 and 2.
Answer
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Control Systems
Angle of asymptotes for complimentary root locus is
(2q+1)*180/P
(2q+1)*180/(P-Z)
(2q)*180/(P-Z)
(2q)*180/P
(2q+1)*180/P
(2q+1)*180/(P-Z)
(2q)*180/(P-Z)
(2q)*180/P
Answer
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Control Systems
For the polynomial , number of roots which lie in the right half of s-plane is
4
1
2
3
4
1
2
3
Answer
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Control Systems
The transfer function of a linear time invariant system is given as G(s) = 10/(s² + 10s + 10). The steady state value of the output of the system for step input applied at time instant t=2 sec will be
1
undefined
infinity
0
1
undefined
infinity
0
Answer
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