EE MCQ

SSC JE Electrical 2019 with solution SET-1
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P = ρQHg is the water power equation. Head ‘H’ is measured in meter ‘g’ gravity constant is measured in meter/second square, then the measuring unit of ‘Q’, the flow rate of water is:

P = ρ QHg is the water power equation.

Where

H = heead = meter

g = gravity =m/s2

ρ =density = (kg/m3)

P = power = watt = N-m/sec

Q = water flow rate = m3/sec

Related Question

SSC JE Electrical 2019 with solution SET-1
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If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

Luminous flux measures the total radiant power reaching a surface, but without regard to surface position: the power might be concentrated on only part of the surface or spread evenly across it.

Irradiance (Ee) or illuminance (Ev) is the density of incident radiant flux or luminous flux at a point on a surface and is defined as radiant flux or luminous flux per unit area, as given by

E = dφ/dA

where (dφ) is the radiant flux or luminous flux incident on an element dA of the surface containing the point. The unit of irradiance is Wm−2, and that of illuminance is lux

SSC JE Electrical 2019 with solution SET-1
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Which of the following is the correct relation regarding coupled coils?

Mutual inductance between two coupled coils is given by the relation

M = K√L1L2

Where

L1L2 = Inductance of the coil

K = Coefficient of coupling

When K = 1 coils are said to be tightly coupled and if K is a fraction the coils are said to be loosely coupled.

Here

Kmax =1

Kmin =0

∴ m ≤ (L1 L2 )0.5

SSC JE Electrical 2019 with solution SET-1
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________ is used to manufacture stay wire, earth wire, and structural components

Galvanized steel conductors do not corrode, and possess high resistance. Hence such Wires are used in telecommunications circuits, earth wires, guard wire, stray wire, etc.

SSC JE Electrical 2019 with solution SET-1
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Identify the important feature of a DC series motor

In DC series motor Torque (Ta) increase as the Square of armature current (Ia) Ta ∝ Ia2. So DC motor provides high starting torque.

SSC JE Electrical 2019 with solution SET-1
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The voltmeter is shown in the circuit reads:

Total resistance in the given circuit

R = (250 + 250)MΩ = 500 MΩ

Current I = V/R = 24/(500 × 103)

Now the Voltage in the voltmeter

= \dfrac{{24}}{{500 \times {{10}^3}}} \times 250 \times {10^3}

V = 12 V