Related Question
Where,
R2 is the resistance connected to the faulty core in ohm
R2 is the resistance of the resistor connected to the sound core in ohm
R1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)
= (15/60)*600
= 150 m
When neutral disconnected Lamp are in series connection,
So, for series connection current is same for both Lamp,
Resistance of Lamp (L1) = (230)²/P
= (230)²/100
= 529 ohm
Resistance of lamp (L2) = (230)²/150
= 352.67 ohm
So, current through the lamp = E/(R1 + R2)
= 400/(529 + 352.67)
= 0.454 A
Voltage across lamp (L1) = I*R1
= 0.454*230
= 240 V
The electrostatic stress in a cable is not uniformly distributed.
The potential gradient is inversely proportional to the distance from the centre of the cable.
Hence, it will be maximum (gmax) at the surface of the conductor and goes on decreasing until it becomes minimum (gmin) at the surface of the sheath.
That means electrostatic stress in the dielectric of a cable is maximum at the surface of the conductor and minimum at the surface of the sheath.
A voltage dip is a short temporary drop in the voltage magnitude in the distribution or customer's electrical system.
Common causes of voltage sags and under voltages are short circuits (faults) on the electric power system, motor starting, customer load additions and large load additions in the utility service area.
Sags can cause computers and other sensitive equipment to malfunction or simply shut off.