EE MCQ

SSC JE Electrical 2019 with solution SET-2
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In excess-three code the 4-bit group that is used is

The excess-3 code for a given decimal number is determined by adding ‘3’ or “0011” to each decimal digit in the given number.

Related Question

SSC JE Electrical 2019 with solution SET-2
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Observe the figure and find the correct relation from the four given options?

According to Kirchhoff’s law states that the current entering a node is always equal to the current leaving a node.

From the above Diagram

Current Flowing towards the Point: I1, I2, I6

Current Flowing Away from the Point: I3, I4, I5

Hence I1 + I2 + I6 = I3 + I4+ I5

SSC JE Electrical 2019 with solution SET-2
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Voltage regulation is considered to be the best for transmission lines?

Voltage Regulation: When the transmission line is energized, the current is flowing in the line. Due to this current, a voltage drop occurs because of the resistance and inductance of the line. So, the receiving-end voltage (VR) is always less than the sending-end voltage (Vs).

The difference produced in the voltage at the receiving end of the transmission line from no load to full load conditions is known as voltage regulation of the line and it is expressed as a percentage of the receiving-end voltage (VR).

It is always desirable that the voltage regulation of the line should be low, or in other words, the increase in the load current should lead to a small difference in the receiving-end voltage.

SSC JE Electrical 2019 with solution SET-2
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A long straight wire carries a current I = 10 A. At what distance is the magnetic field H = 1 A/m?

The strength of a magnetic field is specified by the magnetic induction B or by the magnetic field strength H. A current I through a long, straight wire produces a magnetic field with strength H = I/2πr at a distance r from the wire.

Given

H = 1 A/m

I = 10 A

H = I/2πr

1 = 10/2πr

r = 10/2π

SSC JE Electrical 2019 with solution SET-2
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If the connected light load in a house is 3000W and power sub-circuit load 6000W, then what is the total number of sub-circuits required?

Indian Electricity Rules specify that the maximum load on a light/fan sub-circuit should not exceed 800 watts and the number of points should be limited to 10.

Hence for light load number of sub-circuit = 3000/800 = 3.75 = 4

Indian Electricity Rules specify that the maximum load on a power sub-circuit should not exceed 3000 watts and the number of outlets should be limited to two.

For the power sub-circuit load number of sub-circuit = 6000/3000 = 2

Total subcircuit = 4 + 2 = 6