Condition of good conductor:
σ/ϵω >> 1
Equation is given by:
The constant ratio = σ/ϵω
= 44913.6
σ/ϵω >> 1.
hence sea water is a acting as a good conductor Since attenuation is 90%, so transmission is 10%
So,
e^(-αx) = 0.1
Attenuation constant = √(σμϵ/2)
= 0.702
-αx = ln(0.1)
x = 3.27 m
Related Question
The ratio of full load current to short circuit current = 1/5
Xsc = j/(1/5)
External reactance required = j*((1/5) - 0.05))
= j*0.15 pu
Full load current = (30*1000)/(√3*11)
= 1574.6 A
Per unit reactance = j*0.15 = (I*Xr)/V
j*0.15 = (1574.6*Xb)/((11/√3)*1000))
= 0.60 ohm