EE MCQ

SSC JE Electrical 2019 with solution SET-1
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Find the frequency of rotor induced EMF of a 3-phase, 440V, 50 Hz induction motor has a slip of 10%

Given Data

Voltage = 440 V

Frequency = 50 Hz

Slip = 10% =0.1

Now,

Rotor frequency = slip × frequency

= 0.1 × 50 = 5 Hz

Related Question

SSC JE Electrical 2019 with solution SET-1
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In the full-wave rectifier circuit shown in the figure, the diodes that conduct when the positive half-wave of AC signal applied are

During the positive half cycle of the supply, diodes D1 and D2 conduct are forward biased and conduct current while diodes D3 and D4 are reverse biased and they act as an open circuit, the current flows through the load.

SSC JE Electrical 2019 with solution SET-1
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Hysteresis loss is NOT a function of

Hysteresis Loss = Kh × BM1.67 × f × v watts

where

Kh = Hysteresis constant depends upon the material

Bm = Maximum flux density

f = frequency

v = Volume of the core

Hence the hysteresis loss does not depend upon the ambient temperature.

SSC JE Electrical 2019 with solution SET-1
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If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

Luminous flux measures the total radiant power reaching a surface, but without regard to surface position: the power might be concentrated on only part of the surface or spread evenly across it.

Irradiance (Ee) or illuminance (Ev) is the density of incident radiant flux or luminous flux at a point on a surface and is defined as radiant flux or luminous flux per unit area, as given by

E = dφ/dA

where (dφ) is the radiant flux or luminous flux incident on an element dA of the surface containing the point. The unit of irradiance is Wm−2, and that of illuminance is lux

SSC JE Electrical 2019 with solution SET-1
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Find the mutual inductance between two ideally coupled coils of 2H and 8H

Mutual inductance between the two coils is K = √L1.L2

K = √2 × 8

k = √16

k = 4 H