A single-phase induction motor with only one winding on the stator cannot produce any starting torque. Hence, some extra arrangement is required to start the motor. In the running condition, the motor is capable of developing the torque with only one winding on the stator.
The simplest method of starting is to provide an auxiliary winding on the stator in addition to the main winding. The two windings are placed in the stator with their axes displaced by 90 electrical degrees in space.
Synchronous motors are not self-starting. The DC source is applied to the rotor of the synchronous Motor.
The 2’s complement of the number (1010101)2 is found in two steps. First, convert the given number into its l’s complement.
1’s complement of a binary number is just an inversion of individual bits.
1’s complement of (1010101)2 is (0101010)2
To find 2’s complement of the number add one to the least significant bit (LSB). So
For the given network the potential at point a can be found by applying KVL.
For loop 1
Va = E1 − I1R1
Va = I3R3
For loop 2
Va = E2 − I2R2