To find the Thevenin’s resistance the current source is open-circuited and the voltage source is short-circuited.
Power (P) = 20 kW = 20 × 103 W
Voltage (V) = 200 V
P = VI = I = P/V
I = (20 × 103)/200
I = 100A
For wave wound No. of Parallel Path = 2
Current in Each parallel Path for wave wound
I = 100/2 = 50 A
The factor by which, the induced E.M.F gets reduced due to short pitching is called pitch factor or coil span factor denoted by Kc. It is given as
Kc = cosα/2
α = 60°
Kc = cos60/2
Kc = cos30°
Kc = √3/2
For the given network the potential at point a can be found by applying KVL.
For loop 1
Va = E1 − I1R1
Va = I3R3
For loop 2
Va = E2 − I2R2
In the same way that we can have series, parallel or series-parallel electric circuits, we can also have equivalent series and series-parallel (but not parallel) magnetic circuits.
In practice, a magnetic circuit may consist of several parts in a series of different lengths, cross-sectional areas, and permeabilities. In such a series magnetic circuits, all the reluctances of several parts will get summed up together (as resistors in an electric circuit) to form the net reluctance of the circuit.
In series magnetic circuits the flux passing through each part will be the same (as current in the series electric circuits).