P = S*cosφ
S = P/cosφ
S = 300/0.5
S = 600 kVA
For same kVA rating and unity power factor,
P = 600*1
P = 600 kW
Pextra = 600 - 300
Pextra = 300 kW
Related Question
Maximum permissible load = Rated MVA rating*fraction of rated kVA
Maximum permissible load = 15*1.25
Maximum permissible load = 18.75 MVA
In DC microgrid system,
Efficiency α 1/Pin
For 1 kW loss injecting power is 20 kW
For 1.5 kW loss injecting power will be proportional to 30 kW
So,
Efficiency will be reduced 0.025