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Electromagnetic Field Theory
A waveguide operated below cut off frequency can be used as
An isolator
Phase shifter
An attenuator
None
An isolator
Phase shifter
An attenuator
None
Answer
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Related Question
Electromagnetic Field Theory
Ohm’s law in point from field theory can be expressed as
J = E / σ.
J = σE.
R = ρ × ( l / A).
V = IR.
J = E / σ.
J = σE.
R = ρ × ( l / A).
V = IR.
Answer
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Electromagnetic Field Theory
An electric field of 1.92 × 103 N/C is maintained across two plates separated by 0.015 m. Potential difference across plates will be
28.8 V.
14.40 V.
1.4 V.
2.88 V.
28.8 V.
14.40 V.
1.4 V.
2.88 V.
Answer
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Electromagnetic Field Theory
Which of the following represents ohms law
All of these
V = RI
I = GV
J = σE
All of these
V = RI
I = GV
J = σE
Answer
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Electromagnetic Field Theory
A wire 1 m long carries a current of 5A and is at an angle of 30o with B = 1.5 wb/m2. Magnitude of force is
2.5 N.
2 N.
3.75 N.
5 N.
2.5 N.
2 N.
3.75 N.
5 N.
Answer
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Electromagnetic Field Theory
Electric field intensity (E) at ant point in an electric field is equal to
(potential gradient)2.
(potential gradient)1/2.
potential gradient.
(potential gradient)1/3.
(potential gradient)2.
(potential gradient)1/2.
potential gradient.
(potential gradient)1/3.
Answer
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