A single phase motor connected to 400 V, 50 Hz supply takes 30 A at a power factor of 0.7 lagging. Calculate the capacitance required in parallel with the motor to raise the power factor to 0.9 lagging.

For single phase induction motor,
P = VIcosφ
P = 400*30*0.7
P = 8400 W
Q1 = P*tan(φ) = 8400*1.020
Q = 8568.82 VAR
Now power factor change to 0.9
So, φ' = 25.84 degree
Q = 8400*tan(25.84)
Q = 4067.95
Qnet = Q - Q'
Qnet = 8568.82 - 4067.95
Qnet = 4500.8
C = V²/(2ᴨf)
C = (400*400)/(2ᴨ*50)
C = 8.95*10⁻⁵
C = 89.5 μF

Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 375 W and –50 W. Calculate the reactive power taken by the load.

Reactive power taken, Q = √3*(W1 - W2)
Q = √3*(375 + 50)
Q = √3*425 kVAR

Consider the following statements and choose the correct option:
Statement 1: The magnitude of earth fault current for a given fault position within a winding depends upon the method of neutral grounding.
Statement 2: Earth fault protection for an electric motor is provided by means of instantaneous overcurrent relay.

The magnitude of earth fault current for a given fault position within a winding demands upon the winding connections and method of neutral grounding.
Earth fault protection for an electric motor is provide by instantaneous relay having a setting of approximately 30% of motor rated current in the residual circuits of two CTs and with ground wire.

A given solar cell has the following specifications:
Open-circuit voltage, Voc: 0.7 V
Short-circuit current, Isc: 3.5 A
Short-circuit current, Isc: 3.5 A
Short-circuit current, Isc: 3.5 A
If the solar cell operates at maximum power point, calculate the efficiency.

Equation is given by:
Efficiency = (F.F*Voc*Isc)/Pin
= (0.6*3.5*0.7)/10
= 0.14702
% efficiency = 14.7 %

In computer networks, the nodes are

What is the full form of the acronym 'BCCI' in sports?