A 3-phase motor load has a p.f. of 0.397 lagging. The two wattmeter method used to measure power show the input as 30 kW. Find the reading on each wattmeter.

Here,
Cosφ = 0.397
P = 30 kW = √3*V_L*I_L*cosφ
V_L*I_L = 30kW/(√3*0.397) = 43628.48 VA

Readings of wattmeter W1 = V_L*I_L*cos(30+φ)

Readings of wattmeter W2 = V_L*I_L*cos(30-φ)

જે ક્રિયા દર્શાવે પણ વાક્યનો અર્થ પૂર્ણ કરે એ એને ____કહેવાય. - આપેલ વિકલ્પોમાંથી યોગ્યનું ચયન કરી વાક્ય પૂર્ણ કરો

If all the devices are connected to a central hub, then the topology is called

A three-phase 400 V, 6-pole, 50 Hz squirrel-cage induction motor is running at a slip of 5%. The speed of rotor with respect to stator magnetic field and speed of the stator magnetic field with respect to rotor magnetic field are

Slip, s = (Ns - Nr)/Ns
Ns = 120f/P
0.05 = (1000 - Nr)/1000
Nr = 950 rpm
Speed of rotor with respect to stator magnetic field = 950 - 1000 = -50 rpm

Speed of the stator magnetic field with respect to stator core = 0
Speed of the rotor magnetic field with respect to rotor = sNs
Speed of the stator magnetic field with respect to rotor magnetic field = 0
Speed of the rotor magnetic field with respect to stator core = Ns

Fill in the blanks with suitable Article from the given alternatives.
I heard ____interesting story yesterday

If the velocity of electromagnetic wave in free space is 3 × 10⁸ m/s, then the velocity in a medium with εr of 4.5 and μr of 2 would be

Speed of EM wave in medium = C/√(εr*μr)
= (300000000)/√9
= 300000000/3
= 100000000
= 1*10⁸ m/s