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Electrical Machines
A 230 V, 50 Hz, 4 pole single phase induction motor is rotating in the clockwise ( forward ) direction at a speed of 1425 rpm. If the rotor resistance at standstill is 7.8 ÃŽÂ©. Then the effective rotor resistance in the backward branch of the equivalent circuit will be
2 ÃŽÂ©.
10 ÃŽÂ©.
8 ÃŽÂ©.
4 ÃŽÂ©.
2 ÃŽÂ©.
10 ÃŽÂ©.
8 ÃŽÂ©.
4 ÃŽÂ©.
Answer
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Related Question
Electrical Machines
No load saturation characteristics are plotted between
no load voltage and armature current
short circuit current and armature current
no load voltage and field current
short circuit current and field current
no load voltage and armature current
short circuit current and armature current
no load voltage and field current
short circuit current and field current
Answer
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Electrical Machines
When a short circuit test on a transformer is performed at 25 V, 50 Hz, the drawn current is I1. If the test is performed by 25 V and 25 Hz and power drawn current is I2, then
I1 < I2
None of these
I1 = I2
I1 > I2
I1 < I2
None of these
I1 = I2
I1 > I2
Answer
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Electrical Machines
In one 132 / 33 kV transformer the LV resistance is 0.02 per unit. The resistance referred to HV side is
0.16 pu.
0.08 pu.
0.02 pu.
0.01 pu.
0.16 pu.
0.08 pu.
0.02 pu.
0.01 pu.
Answer
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Electrical Machines
A 220 ,V 15 , kW 100 rpm shunt motor with armature resistance of 0.25 , W has a rated line current of 68 A and a rated field current of 2.2 A. The change in field flux required to obtain a speed of 1600 rpm while drawing a line current of 52.8 A and a field current of 1.8 A is
36.36% increase
36.36% increase
36.36% decrease
18.18% increase
36.36% increase
36.36% increase
36.36% decrease
18.18% increase
Answer
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Electrical Machines
Which of the following is/are the methods to reduce the armature reaction and its effects?
All of these
pole stacking
pole chamfering
compensating winding
All of these
pole stacking
pole chamfering
compensating winding
Answer
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